Question

Find three consecutive odd integers such that the sum of the three numbers is 60 less than the square of the largest integer

Answer 1

Answer: 5, 7 and 9

Step-by-step explanation:

Let m-2, m and m+2 be the three consecutive odd integers

Then, it is given that sum of them is 60 less than the square of the largest integer.

(m-2) + m + (m+2)=(m+2)²-60

3m=m²+4m-56

m²+m-56=0

(m-7)(m+8)=0

m=7 as m= -8 is not possible as m is an odd number

So the numbers are 5, 7 and 9