Question

find three consecutive odd integers whose sum is 57

Answer 1

Let the odd integers be x, x+2, x+4
According to the question.
x+x+2+x+4=57
3x+6=57
3x=57-6
3x=51
x=51/3=17
Hence, x+2=19, x+4= 21

Answer is 17, 19, and 21

Answer 2

Answer:

The three consecutive odd integers are $17,19$ and $21$.

Step-by-step explanation:

To find:-

The $3$ consecutive odd integers whose sum is $57$.

Step 1 of 1

Let the three odd consecutive integers be 2x + 1, 2x + 3 and 2x + 5.

According to the question,

The sum of three consecutive odd integers is 57, i.e.,

2x + 1 + 2x + 3 + 2x + 5 = 57

Add all the like terms as follows:

6x + 9 = 57

6x = 57 - 9

6x = 48

x = 8

Thus, three consecutive odd integers are:

2x + 1 = 2(8) + 1

         = 17

2x + 3 = 2(8) + 3

         = 19

2x + 1 = 2(8) + 5

         = 21

Therefore, the $3$ consecutive odd integers are $17,19$ and $21$.

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