Question

find three consecutive odd intergers such that the sum of twice the first the second and three times the third is 152

Answer 1

Let the numbers be 2x+1, 2x+3,2x+5
According to question,
2(2x+1) + 2x+3 + 3(2x+5) = 152
4x + 2 + 2x +3 + 6x +15 = 152
12x + 20 = 152
12x = 132
X = 11
The consecutive terms are 23, 25,27

Answer 2

Let the three consecutive odd number is
X,(X+2),(X+4)--------(1)
A/c to given condition:
2(X)+(X+2)+3(X+4)=152
2X+X+2+3X+12=152
6X+14=152
6X=152-14
X=138/6
X=23
Put this value of X in eq(1)
23,25,27 are the consecutive odd numbers