Find three consecutive odd natural number whose sum is 87.
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Answers
Answered by
13
Let the first number be a
Second number = a +2
Third number = a + 4
According to question
a + a +2+a + 4 = 87
=> 3a + 6 = 87
=> 3a = 81
=> a = 27
First number = 27
Second number = 29
Third number = 31
Second number = a +2
Third number = a + 4
According to question
a + a +2+a + 4 = 87
=> 3a + 6 = 87
=> 3a = 81
=> a = 27
First number = 27
Second number = 29
Third number = 31
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Answered by
2
Let one of the numbers be x
The other two numbers are x+2, x+4 ( since it is asked about consecutive odd numbers)
According to the question,
=>x + ( x+2) + ( x+ 4) = 87
=>x + x + x + 2 + 4 = 87
=>3x + 6 = 87
=>3x = 87 - 6
=>3x = 81
=>x = 27
The other two numbers are 27 + 2 = 29
27 + 4 = 31
Therefore the numbers are 27, 29,31
The other two numbers are x+2, x+4 ( since it is asked about consecutive odd numbers)
According to the question,
=>x + ( x+2) + ( x+ 4) = 87
=>x + x + x + 2 + 4 = 87
=>3x + 6 = 87
=>3x = 87 - 6
=>3x = 81
=>x = 27
The other two numbers are 27 + 2 = 29
27 + 4 = 31
Therefore the numbers are 27, 29,31
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