Question

find three consecutive odd natural numbers whose sum is 87

Answer 1

Let the no.s be x, x+2, x+4
A/Q x+(x+2)+(x+4) = 87
3x+6 = 87
3x = 81
x = 84/3 = 27
∴ First no. = x = 27
Second no. = x+2 = 27+2 = 29
Third no. = x+4 = 27+4 = 31

Answer 2

Let one of the numbers be x
The other two numbers are x+2, x+4 ( since it is asked about consecutive odd numbers)
According to the question,
=>x + ( x+2) + ( x+ 4) = 87
=>x + x + x + 2 + 4 = 87
=>3x + 6 = 87
=>3x = 87 - 6
=>3x = 81
=>x = 27

The other two numbers are 27 + 2 = 29
                                               27 + 4 = 31
Therefore the numbers are 27, 29,31