find three consecutive odd natural numbers whose sum is 87
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Answered by
4
Let the three consecutive odd numbers be X and ×+2 and ×+4
then by given condition
×+(×+2)+(×+4)=87
2x+2+×+4=87
3×+6=87
3×=81
×=27
therfore three odd numbers will be
×=27
×+2=29
and x+4=31
hope it helps!
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Answered by
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Let three consecutive odd natural numbers be x, x+2, x+4
A.T.Q.
x + x+2 + x+4 = 87
3x + 6 = 87
3x = 87 - 6
x = 27
Hence, three consecutive odd natural numbers are 27,29,31.
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