Question

Find three consecutive odd natural numbers whose sum is more than 63 but less than 81​

Answer 1

Step-by-step explanation:

Then the three numbers are (x-1), x and (x+1). You are given that (x-1) + x + (x+1) = 81, or, which is the same, 3x = 81. Hence, x = = 27. So, yournumbers are 26, 27 and 28.

Answer 2

The three consecutive odd natural numbers whose sum is more than 63 but less than 81​ are 21 , 23 , 25 or 23 , 25 , 27.

Explanation:

Let the three odd consecutive numbers are x , x+2 , x+4.

According to the question , we have

$63 <x+x+2+x+4<81\\\\\Rightarrow\ 63<3x+6<81$

$\Rightarrow\ 57< 3x< 75$  [Subtract 6 from all sides]

$\Rightarrow\ 19 < x < 25$  [Divide three from all sides]

So , the x must be an number that is greater than 19 but smaller than 25 and they are 21 and 23.

So x can be either 21 or 23.

If x= 21 , then the required three odd consecutive odd natural numbers  would be 21 , 23 , 25

If x =23 , then the required three odd consecutive odd natural numbers  would be 23 , 25 , 27.

Both are valid.

Hence, the three consecutive odd natural numbers whose sum is more than 63 but less than 81​ are 21 , 23 , 25 or 23 , 25 , 27.

# Learn more :

The sum of three consecutive odd natural number is 123.find the number

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