Question

find three consecutive odd no. whose sum is 147.
explain it properly...

Answer 1

Your answer is here

Let the three consecutive odd numbers be (x+1),(x+3)and(x+5)
A/q,
$x + 1 + x + 3 + x + 5 = 147 \\ \\ 3x + 9 = 147 \\ \\ 3x = 147 - 9 \\ \\ 3x = 138 \\ \\ x = \frac{138}{3} \\ \\ x = 46$
Required numbers

x+1 = 46+1 = 47

x+3 = 46 + 3 = 49

x+5= 46 + 5 = 51

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