Find three consecutive odd number whose some is 147
Answers
Answered by
0
let the number be x x+2 x+4
x+x+2x+4=147
3x+6=147
3x=141
x=47
the numbers are 47 49 51
x+x+2x+4=147
3x+6=147
3x=141
x=47
the numbers are 47 49 51
Answered by
0
3 numbers are 47,49,51.
Similar questions