Find three consecutive odd number whose sum equal 741.
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Let the first odd no- x
Then, the second odd no- (x+2)
Then, the third odd no- x+4
=(x)+(x+2)+(x+4)= 741
=3x+6= 741
=3x= 741-6= 735
=x= 735/3= 245
So, the three numbers are-
1. x= 245
2. (x+2)= 245+2= 257
2. (x+4)= 245+4= 259
Hope this helps!
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