find three consecutive odd number whose sum is 147
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let the consecutive no. be x,(x+2),(x+4)
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A.T.Q
x+x+2+x+4=147
3x+6=147
3x=147-6
3x=141
x=141/3
x=47
Hope u understand.....
______________
¶¶¶¶¶¶¶¶¶¶¶¶¶§§§§§§§§§§§§
A.T.Q
x+x+2+x+4=147
3x+6=147
3x=147-6
3x=141
x=141/3
x=47
Hope u understand.....
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