Math, asked by khushishukla2, 1 year ago

find three consecutive odd number whose sum is 147.

Answers

Answered by RiShIkÄÇhäÑdR
6
Let three consecutive odd number be x, x + 2 and X + 4.

According to the question,

x + X + 2 + X + 4 = 147
3 X + 6 = 147
3 x = 147 - 6
X = 141 / 3
x = 47.

x+q = 47 +
= 49

x + 4 = 47 +4
= 51.

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Answered by KanikAb
2
Let the three consecutive odd numbers be x+1,x+3, and x+5 According to the equation ,
x+1+x+3+x+5=147
=>3x+6=147
=>3x+6-147=0
=>3x-141=0
=>x=47
Therefore, the three consecutive odd numbers are 48, 50,and 52
Hope you will understand what i have typed there.... :-)

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