find three consecutive odd number whose sum is 147.
Answers
Answered by
6
Let three consecutive odd number be x, x + 2 and X + 4.
According to the question,
x + X + 2 + X + 4 = 147
3 X + 6 = 147
3 x = 147 - 6
X = 141 / 3
x = 47.
x+q = 47 +
= 49
x + 4 = 47 +4
= 51.
If you find my answer helpful plz mark it as a brainliest answer friend ..
According to the question,
x + X + 2 + X + 4 = 147
3 X + 6 = 147
3 x = 147 - 6
X = 141 / 3
x = 47.
x+q = 47 +
= 49
x + 4 = 47 +4
= 51.
If you find my answer helpful plz mark it as a brainliest answer friend ..
KanikAb:
ur ans is wrong check out...
n i hv checkd my no. and the fact is that my ans is correct
sry chckd my ans
are yll thik h n
kyu jal ri h
wr jal ri h..... y u dint c ur mistk
u r tryng to cvr it
okkk mt ro
Chup ho ja
nipple du kya
Answered by
2
Let the three consecutive odd numbers be x+1,x+3, and x+5 According to the equation ,
x+1+x+3+x+5=147
=>3x+6=147
=>3x+6-147=0
=>3x-141=0
=>x=47
Therefore, the three consecutive odd numbers are 48, 50,and 52
Hope you will understand what i have typed there.... :-)
x+1+x+3+x+5=147
=>3x+6=147
=>3x+6-147=0
=>3x-141=0
=>x=47
Therefore, the three consecutive odd numbers are 48, 50,and 52
Hope you will understand what i have typed there.... :-)
plz be in your limits
u bttr stay in ur limits
Similar questions