Math, asked by harishmalik123123, 1 month ago

find three consecutive odd number whose sum is 147​

Answers

Answered by yourdreamworldof2020
0

Answer:

47,49 and 51

Step-by-step explanation:

Let the three consecutive numbers be (x), (x+2) and (x+4)

we can write x  + x + 2 + x + 4 = 147

On simplifying we get 3x+6=147

On rearranging we get

3x = 147 – 6

3x = 141

x = 141/3 = 47

So the numbers are (2)=47

(x+2) = 49

(x+4) = 51

Answered by KAUSHALGAJPAL
0

Answer:

halves of a few minutes 8639(3883)>#/+)+74h+-8

Similar questions