find three consecutive odd number whose sum is 147
Answers
Answered by
0
Answer:
47,49 and 51
Step-by-step explanation:
Let the three consecutive numbers be (x), (x+2) and (x+4)
we can write x + x + 2 + x + 4 = 147
On simplifying we get 3x+6=147
On rearranging we get
3x = 147 – 6
3x = 141
x = 141/3 = 47
So the numbers are (2)=47
(x+2) = 49
(x+4) = 51
Answered by
0
Answer:
halves of a few minutes 8639(3883)>#/+)+74h+-8
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