Question

find three consecutive odd number whose sum is 147 [hint - let the required number be (2x+1),(2x+3)and (2x+5)] ​

Answer 1

Answer:

Let the numbers be (2x+1) (2x+3) (2x+5) because any number multiplied by 2 is even and adding 1 gives an odd number. Now,

(2x+1) + (2x+3) + (2x+5) = 147

2x+1 + 2x+3 + 2x+5 = 147

6x+9 = 147

6x = 147-9

6x = 138

x = 138÷6

x = 23

First No. = 2x+1

= 2×23+1

= 47

Second No. = 2x+3

= 2×23+3

= 49

Third No. = 2x+5

= 2×23+5

= 51

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Answer 2

Answer:

Step-by-step explanation:

Actually the answer is 1st No. is 47 and the 2nd No. is 49 and the 3rd one 51.