find three consecutive odd number whose sum is 333
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Answer:X + X + 1 + X + 2 = 333
3X + 3 = 333
3X + 3 - 3 = 333 - 3
3X = 330
3X/3 = 330/3
X = 110
Which means that the first number is 110, the second number is 110 + 1 and the third number is 110 + 2. Therefore, three consecutive integers that add up to 333 are 110, 111, and 112.
110 + 111 + 112 = 333
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