Question

Find three consecutive odd numbers when three times of their sum is 5 more than
8 times the middle number.​

Answer 1

Answer:

3,5, and 7 are the three consecutive odd integers

Explanation:

x = 1st odd integer

x + 2 = 2nd odd integer

x + 4 = 3rd odd integer {odd and also even integers increase by 2}

3(x + x + 2 + x + 4) = 8(x + 2) + 5 {sum is equal to 5 more than 8 times the middle one}

3(3x + 6) = 8x + 16 + 5 {combined like terms on left, used distributive property on right}

9x + 18 = 8x + 21 {combined like terms}

x = 3 {subtracted 8x and subtracted 18 from each side}

x + 2 = 5 {substituted 3, in for x, into x + 2}

x + 4 = 7 {substituted 3, in for x, into x + 4}

3,5, and 7 are the three consecutive odd integers

Answer 2

Answer:

The answer is 3, 5 , 7.

Explanation:

Hope it helps

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