Question

Find three consecutive odd numbers when three times of their sum is 5 more than 8 times the middle number. ​

Answer 1

Answer:

3, 5 and 7.

Step-by-step explanation:

Let the required numbers be x, x + 2 and x + 4 respectively.

Then, 3(x + x + 2 + x + 4) = 5 + 8(x+2)

⇒3(3x + 6) = 5 + 8x + 16

⇒9x + 18 = 21 + 8x

⇒9x - 8x = 21 - 18

⇒x = 3

So, the numbers are 3, 5 and 7.

-$Shahrin$ $Khan$