Question

find three consecutive odd numbers whose. sum is 147.​

Answer 1

Answer:

Let three consecutive numbers be-

x-2 , x , x+2

As, x-2+x+x+2 = 147

=> 3x = 147

=> x = 147/3

=> x = 49

Then, the three numbers are- 47,49,51

Step-by-step explanation:

Hope it Helps✌

Answer 2

Answer:

47, 49, 51

Step-by-step explanation:

So to find your range to begin in, simply do 147/3, and you get 49. From there, you can assume that the other two consecutive odd numbers are 47 and 51. Add them together and what do you get? BIBITY BOBITY BOOO, or in other words, 147:))))) HOPE THIS HELPED! (Please give me a brainliest, I REALLY need one.:))