Question

find three consecutive odd numbers whose sum is 147

Answer 1

Let the three odd numbers be x,x+2,x+4
Now,
$A/Q$
$x + x + 2 + x + 4 = 147 \\ = > 3x + 6 = 147 \\ = > 3x = 141 \\ = > x = \frac{141}{3} \\ = > x = 47$
So the three odd numbers are, 47,49,51

Answer 2

Answer:

x = 141/3

x = 47

Hope it will be helpful ✌️