Find three consecutive odd numbers whose sum is 267
Answers
Answered by
0
Step-by-step explanation:
x+x+2+x+4=267
3x+6=267
3x=261
x=261/3
x=87
therefore the numbers are 87,89 and91
Answered by
0
The digits are
88
,
89
,
90
Explanation:
Let the starting digit be
x
Then the other two digits are -
x
+
1
x
+
2
Form an equation
x
+
(
x
+
1
)
+
(
x
+
2
)
=
267
Solve it
x
+
x
+
1
x
+
2
=
267
3
x
+
3
=
267
3
x
=
267
−
3
=
264
x
=
264
3
=
88
The first digit is
88
The second digit is
89
The third digit is
90
88
,
89
,
90
Explanation:
Let the starting digit be
x
Then the other two digits are -
x
+
1
x
+
2
Form an equation
x
+
(
x
+
1
)
+
(
x
+
2
)
=
267
Solve it
x
+
x
+
1
x
+
2
=
267
3
x
+
3
=
267
3
x
=
267
−
3
=
264
x
=
264
3
=
88
The first digit is
88
The second digit is
89
The third digit is
90
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