Question

find three consecutive odd numbers whose sum is 273​

Answer 1

Answer:

let the numbers be x , x+1, x+2

x+x+1+x+2=273

3x+3=273

3x=273-3

3x=270

x=270÷3

x=90

x+1=90+1=91

x+2=90+2=92

hence the sum of consecutive three odd numbers are 90, 91,92...

Answer 2

Concept:

In an arithmetic progression, the differences between every two succeeding words are the same. It's possible to find a formula for the AP's nth phrase using an arithmetic progression. An AP is a series in which each term, save the first, is generated by multiplying its previous term by a specified integer. The "fixed number" is indicated by 'd' and is called the "common difference."

Find:

The three consecutive numbers.

Solution:

Let the three consecutive odd numbers be $a, a+2, a+4$.

$a+a+2+a+4=273\\3a+6=273\\3a=267\\a=89$

Hence, the three consecutive odd numbers are $89,91,93$.

#SPJ3