Question

Find three consecutive odd numbers whose sum is 45.

Answer 1

Answer:

13, 15 and 17

Step-by-step explanation:

Let three consecutive odd no. be 2x + 1, 2x + 3 and 2x + 5.

Then,

(2x + 1) + (2x + 3) + (2x + 5) = 45

⇒ 6x + 9 = 45

⇒ 6x = 45 - 9

⇒ 6x = 36

⇒ x = $\dfrac{36}{6}$

∴ x = 6

So  the required no. are 2 × 6 + 1, 2 × 6 + 3 and 2 × 6 + 5, i.e., 13, 15 and 17.

Check:

13 + 15 + 17 = 45

Answer 2

Answer:

13,15 and 17

Step-by-step explanation:

Let us say that the numbers are a , a + 2 , a + 4 .

Consecutive numbers always differ by 2.

For example :

1 , 3 , 5 ........

Hence their sum is given 45 .

This means that :

a + a + 2 + a + 4 = 45

= > 3 a + 6 = 45

= > 3 a = 45 - 6

= > 3 a = 39

= > a = 39/3

= > a = 13

Hence a is 13 .

a + 2 = 13 + 2 = 15

a + 4 = 13 + 4 = 17

Hence the numbers are 13,15 and 17 .