Question

Find three consecutive odd numbers whose sum is 45.

Answer 1

Let x , x+2 and x+4 be three odd numbers

x,x+2,x+4=45

3x+6=45

3x=45-6

3x=9

x=39/3

x=13

answer for the smallest number

13+2=15 for the middle number

13+4=17 answer for the largest number

proof 13 +15 +17 =45

45=45

Answer 2

$\huge{\mathfrak{\underline{Solution}:}}$


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Let the three consecutive odd numbers be 2x + 1, 2x + 3, 2x + 5.

Then,

$\sf (2x + 1) + (2x + 3) + (2x + 5) = 45 \\ \sf \to 6x + 9 = 45 \\ \sf \to 6x = 45 - 9 \\ \sf \to x = \frac{36}{6} \\ \to \sf x = 6$

So,

The First Number = 13

The Second Number = 15

The Third Number = 17