Question

Find three consecutive odd numbers whose sum is 93

Answer 1

Let first number be x
x+x+2+x+2+2=93
3x+6=93
3x=93-6
3x=87
x=87÷3
x=29
1st no. 29
2nd no.31
3rd no.33

Answer 2

Answer:

Number 1 : 29

Number 2: 31

Number 3: 33

Step-by-step explanation:

Concept:

1. Odd numbers are the numbers which give remainder 1 when divided by 2.
2. For example 3/2 gives remainder 1 so, 3 is a odd number.
3. So, let us for example take 3,next number of 3 is 4.
4. 4/2 gives remainder 0 so 4 is not an odd number it is even number.
5. After 4 comes 5 when we divide 5 by 2 we get remainder 1. So, 5 is a odd number.

So, here we can observe a sequence for odd numbers when they are consecutive.

3 is odd number and adding 2 to it gives 5 which is also an odd number.

Next adding 2 to 5 gives 7 which is also an odd number.

So, if we assume x as an odd number it's next consecutive odd number would be x+2 and it's next consecutive odd number is x + 2 + 2.

Solution:

$(x) + (x+2) + (x+2+2) = 93\\x + x + 2 + x + 4 = 93\\3x + 6 = 93\\3x = 87\\x = 87 /3 \\x = 29$

So, first number is 29

Second number is x + 2 = 29 + 2 = 31

Third number is x + 2 + 2 = 29 + 2 + 2 = 33

So, the numbers are 29,31,33

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