Question

find three consecutive odd numbers whose sum is 93

Answer 1

Let the no.s be x, (x+1) and (x+2).

Therefore, x+x+1+x+2= 93
x+x+x+1+2=93
3x+3=93
3x=93-3
=90

Thus, x= 90/3
=30
Hence, the 1st no.=x=30,
2nd no.=(x+1)=30+1=31
3rd no.=(x+2)=30+2=32

Therefore, the three consecutive numbers are 30, 31 &32

Answer 2

here, let first number be x..
then , the second number will be x+2 and the third one will be x+4..
now , x+(x+2)+(x+4)=93..
then, x = 29
so the numbers are 29,31 and 33.