Find three consecutive odd numbers whose sum is147
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Answer:
Hey mate. Here's your answer.
Step-by-step explanation:
Let the three consecutive odd nos. be x+1, x+3 and x+5.
According to the question, (x+1)+(x+3)+(x+5)= 147
→x+1+x+3+x+5= 147
→ 3x+9= 147
→ 3x= 147-9
→ 3x=138
→ x= 138/3= 46
So, the there consecutive odd numbers are:-
x+1= 46+1= 47
x+3= 46+3= 49
x+5= 46+5= 51.
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