Question

find three consecutive positive even integer whose sum is 90

Answer 1

Let the positive even numbers be n, n+2, n+4
Given that n+n+2+n+4=90
3n+6=90
3n=84
n= 28
Therefore the numbers are 28, 30, 32.

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Answer 2

Step-by-step explanation:

Let x is first positive even integer  

(x+2) is second positive even integer

(x+4) is third positive even integer.

According to the question that the sum of three consecutive positive even integer is 90. So,

$x+x+2+x+4=90\\\\3x+6=90\\\\3x=84\\\\x=28$

So,

(x+2) = 30

(x+4) = 32

So, three consecutive positive even integers are 28, 30 and 32.