Find three consecutive positive even integers that sum is 90.
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Answered by
8
Let the positive even numbers be n, n+2, n+4
Given that n+n+2+n+4=90
3n+6=90
3n=84
n= 28
Therefore the numbers are 28, 30, 32.
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Given that n+n+2+n+4=90
3n+6=90
3n=84
n= 28
Therefore the numbers are 28, 30, 32.
If u find it useful then please mark it as brainliest
Answered by
4
So,
The three consecutive positive even integers are-
x+2 = 26 + 2 = 28.
x+4 = 26 + 4 = 30.
x+6 = 26 + 6 = 32.
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