Question

find three consecutive positive even integers whose sum is 90.

Answer 1

hello users ....

solution:-
let;
first positive even integer = x 
Second = (x + 2) 
third = (x + 4)   
Because; these three numbers are consecutive even numbers.

Now;
According to question 
x + (x + 2) + ( x + 4) = 90 

=> 3x + 6 = 90 

=> 3x = 90 - 6 = 84 

=> x = 84 / 3 = 28 

Hence:
three positive even numbers are
x = 28 
second = ( x + 2) = 28 + 2 = 30 
third = ( x + 4 ) = 28 + 4 = 32  Answer 

# hope it helps :) 

Answer 2

Heya user,

Generally, three consecutive even integers are taken as :-->

--> 2 ( k - 1 ) , 2k , 2 ( k + 1 ) -----------> [ For the sake of convinience of solving problems ]

Now, Adding the three, 
---> 2k - 2 + 2k + 2k + 2 = 6k = 90
==> k = 15

And hence, the consecutive even no. are :--> [ 2k - 2 ] = 28.
----------------------------> 2k = 30
----------------------------> 2k + 2 = 32