Question

Find three consecutive positive even integers whose sum is 90.​

Answer 1

$\large\underline{\sf{Solution-}}$

➣We know, consecutive even integers are differ by 2.

So, Let Assume that,

↝ First positive even integer be x

↝ Second positive even integer be x + 2

↝ Third positive even integer be x + 4

➣According to statement,

↝ Sum of three consecutive even positive integer is 90.

So,

$\rm :\longmapsto\:x + x + 2 + x + 4 = 90$

$\rm :\longmapsto\:3x + 6 = 90$

$\rm :\longmapsto\:3x = 90 - 6$

$\rm :\longmapsto\:3x =84$

$\bf\implies \:x = 28$

Hence,

↝ First positive even integer = x = 28

↝ Second positive even integer = x + 2 = 28 + 2 = 30

↝ Third positive even integer = x + 4 = 28 + 4 = 32

Verification :-

↝ First positive even integer = 28

↝ Second positive even integer = 30

↝ Third positive even integer = 32

↝ So, sum of 3 integers = 28 +30 + 32 = 90

Hence, Verified