Math, asked by shivam2819, 1 year ago

find three consecutive positive even integers whose sum is 60

Answers

Answered by siddhartharao77
9

Let the consecutive even positive integers be x,x + 2, x + 4.

Given that their Sum is 60.

⇒ x + x + 2 + x + 4 = 60

⇒ 3x + 6 = 60

⇒ 3x = 54

⇒ x = 18.

Then,

⇒ x + 2 = 20

⇒ x + 4 = 22.


Therefore, the three positive even integers are 18,20,22.


Hope this helps!

Answered by Anonymous
2
\huge\boxed{Solution}

<b><i> Given :-

sum of positive integer = 60

let the three consecutive even integer are

x, x+2 , x+4

So

x+x+2 +x+4 = 60

3x +6 = 60

3x = 60- 6

3x =54

X = 54 / 3

X = 18

So three consecutive number are

X = 18

second = x+2 = 18+2 = 20

third = x+4 = 18 +4 = 22

\boxed {answer is 18, 20 , 22}
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