find three consecutive positive even integers whose sum is 60
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Answered by
9
Let the consecutive even positive integers be x,x + 2, x + 4.
Given that their Sum is 60.
⇒ x + x + 2 + x + 4 = 60
⇒ 3x + 6 = 60
⇒ 3x = 54
⇒ x = 18.
Then,
⇒ x + 2 = 20
⇒ x + 4 = 22.
Therefore, the three positive even integers are 18,20,22.
Hope this helps!
Answered by
2
Given :-
sum of positive integer = 60
let the three consecutive even integer are
x, x+2 , x+4
So
x+x+2 +x+4 = 60
3x +6 = 60
3x = 60- 6
3x =54
X = 54 / 3
X = 18
So three consecutive number are
X = 18
second = x+2 = 18+2 = 20
third = x+4 = 18 +4 = 22
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