Question

Find three consecutive positive integer whose product is equal to the 16 times their sum

Answer 1

Let no. = x,x+1,x-1

(X-1)(x)(x+1)=16(x+x+1+x-1)

(X^2-1)x=48x

X^2-1=48

X^2= 49

X= 7

-7 rejected bcs no. Is positive

Therefore no.s are 6,7,8

Verify

6×7×8 = 336

16(6+7+8) = 336

Hence proved

@skb