Question

find three consecutive positive odd integers whose sum is 99​

Answer 1

Explanation:

Let us call our odd integers:
2n+1
2n+3
2n+5
and write our condition as:
(2n+1)+(2n+3)+(2n+5)=99 and solve it for n:
6n+9=99
6n=90
n=906=15
so our numbers will be:
2n+1=31
2n+3=33
2n+5=35

Answer:

I found 31,33,35

Answer 2

let the three consecutive no. be x,x+1,x+3

sum=99

so x+x+1x+3=99

=3x+4=99

=x+4=33

=x=29

hence x=29

x+1=30

x+3=32