Math, asked by badgurl05, 10 months ago

find three consecutive smallest numbers such that difference between one fourth of the largest and one fourth of the smallest is atleast 3


can som1 pls answer this question asap​

Answers

Answered by Archita893
2

Heya user

Let's the number be

n, n+1 , n+2

according to question..

(n+2)/3 - (n/5) > 3

(5n+10-3n)/15 > 3

2n + 10 > 45

2n = 35

n = 17.5

integer greater than 17.5 is 18

thus the three smallest number satisfying the condition are.. "18,19 and 20"

I hope it will help you..

Similar questions