Question

find three consecutive term in AP whose sum is 9 and product of their cubes is 3375​

Answer 1

Answer:

1,3,5

Step-by-step explanation:

Let the three consecutive terms be a-d ,a ,a+d

Sum =9

a-d+a+a+d=9

3a=9

a=9/3

a=3.

Sum of cubes of first n natural numbers =3375

(a-d)³×(a)³×(a+d)³=3375

(3-d)³×3³×(3+d)³=3375

[(3-d)(3+d]³=3375/27

3²-d²=cube root 125

9-d²=5

9-5=d²

d=√4

d=2

Therefore the numbers are a-d=3-2=1;a=3; a+d=3+2=5