Find three consecutive terms in an A.P. such that their sum is 24 and their product is 440.
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if the the consecutive terms are x , x+1 , x+2
then , here it is given that x( x + 1 ) ( x + 2 ) = 440
and x + x + 1 + x + 2 = 24
3x + 3 = 24
3x = 24 - 3
3x = 21
x = 21 / 3
x = 7
then x is 7 and the remain two terms are 8 and 9
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