Question

find three consecutive terms in an A.P. whose sum is -3 and product of their cubes is 512. (assume the three consecutive terms in A.P. are a-d,a,a+d)

Answer 1

Answer:

three consecutive terms a+b,a,a-b

sum of the three consecutive term:

(a+b)+a+(a-b) = -3

3a =-3

a = -1

a+b x a x a+b = 512

a(+ b x 1 x + b)

2b = -512

b = -256

Hence by substituting the value of A and b you can find the answer of three consecutive terms in an A.P