Question

find three consecutive terms in AP
whose sum is 9 and the product of there cubes is 3375​

Answer 1

(n+d)+(n)+(n-d)=9

3n=9

n=3

therefore you get n=3

now

(3+d)(3)(3-d)=3√3375

9+3d(3-d

27-9d+9d-3d^2

27-3d^2=3√3375

27-3d2=15

d=2

THEREFORE NUMBERS ARE

1,3,5