Find three consecutive whole integer whose sum is 57
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Answer:
Let x = the first integer
Let x + 1 = the second integer
Let x + 2 = the third integer
Now write an equation:
x + (x + 1) + (x + 2) = 57
Combine like terms:
3x + 3 = 57
3x = 57 - 3
3x = 54
x = 18
Now substitute:
x = 18
x + 1 = 19
X + 2 = 20
Your consecutive integers are 18, 19, and 20
jinsa:
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here's ur answer
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