find three consecutive whole number such that three times the middle number greater than the sum of the other two by 11
Answers
Answered by
0
let x,x+1,x+2 are three consecutive whole numbers
3 times of middle number = 3(x+1)=3x+3----(1)
sum of other two numbers = x+x+2=2x+2---(2)
given
(1) - (2)=11
3x+3 -(2x+2)=11
3x+3-2x-2=11
x+1=11
x=11-1
x=10
therefore
required numbers are
x,x+1,x+2
10,11,12
3 times of middle number = 3(x+1)=3x+3----(1)
sum of other two numbers = x+x+2=2x+2---(2)
given
(1) - (2)=11
3x+3 -(2x+2)=11
3x+3-2x-2=11
x+1=11
x=11-1
x=10
therefore
required numbers are
x,x+1,x+2
10,11,12
Similar questions