Find three consecutive whole number whose sum is more than 45
Answers
Answered by
0
Step-by-step explanation:
any three consecutive numbers grater than 14 will have a sum more than 45 .
if you want 45 as a answer the answer is 14, 15 and 16
Answered by
4
answer:
14,15,16
Step-by-step explanation:
let the consecutive no. be x,(x+1),(x+2)
x+(x+1)+(x+2) =45
x+x+1+x+2=45
3x+3 =45
3x =45-3
3x =42
x =42/3
x =14
So the consecutive numbers are
x=14
x+1=15
x+2=15
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