Find three consecutive whole numbers such that three times the middle number is greater than the sum of the other two by 11
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1st:x-1
2nd:x
3rd:x+1
equation: 3x = 2x+1
x = 11
1st:x-1=10
2nd:x=11
3rd:x+1=12
2nd:x
3rd:x+1
equation: 3x = 2x+1
x = 11
1st:x-1=10
2nd:x=11
3rd:x+1=12
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