find three consecutive whole numbers whose sum is more than 45 but less than 54
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2
your answer is 14, 15, 16 which gives 45
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0
(x)+(x+2)+(x+4)=54
x+2x+4x. =54
7x. =54
x. =8
x=8
x+2=8+2=10
x+4=8+4=12
x+2x+4x. =54
7x. =54
x. =8
x=8
x+2=8+2=10
x+4=8+4=12
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