Question

Find three consecutivenaturalnumber is one of 39 find thee other

Answer 1

There are some mistakes in your question. The corrrect one is :-

$\textsf{Question}$ :- Find three consecutive natural numbers whose sum is 39.


$\textsf{Solution}$ :-

Let the three consecutive natural numbers be x, x + 1 and x + 2

Their sum is 39


According to the given condition

x + x + 1 + x + 2 = 39

☛ 3x + 3 = 39

☛ 3x = 39 - 3

☛ 3x = 36

∴ x = 12


∴ 1st natural number ☛ x

☛ $\boxed{\boxed{\tt{12}}}$


∴ 2nd natural number ☛ x + 1

☛ 12 + 1

☛ $\boxed{\boxed{\tt{13}}}$


∴ 3rd natural number ☛ x + 2

☛ 12 + 2

☛ $\boxed{\boxed{\tt{14}}}$

Answer 2

$\underline{\mathfrak{\huge{The\:Question:}}}$

Find three consecutive natural numbers who have their sum equal to 39.

$\underline{\mathfrak{\huge{Your\:Answer:}}}$

Let the numbers be = x, x + 1, x + 2

We've chosen these kinds of numbers just because the numbers are consecutive

=》 x + x + 1 + x + 2 = 39

Solve it further

=》 3x + 3 = 39

Some more steps to go

=》 3x = 36

Last one step

=》 x = 12

Find the other numbers now. Just put the value of x, which is 12, in both the other equations and then find the other two numbers

x + 1 = 13

The last number will be

x + 2 = 14

Thus, the numbers are $\tt{12, 13, 14}$