find three consecutivenumbers such that if they are dividedby10,17,and26 respectively ,the sum of tjeir quotient will be 10
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Answer: Let the consecutive number be x, x+1 and x+2
If they are divided by 10,17and 26 respectively
Then, x÷ 10 + x+1 ÷ 17 + x+12÷ 26 = 10
442x + (260) (x+1) + (170) ( x+2) = 442 × 100
872x+600 = 442× 100
X = 50
So, The consecutive numbers are 50,51,52
Step-by-step explanation:
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