find three consucative term of anA.P. whose sum is 24 and product is 312
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Step-by-step explanation:
let a-d+a+a+d=24.....(1)
(a-d)(a)(a+d)=312........(2)
1... a-d +a +a+d =24
-d and +d cancel
then 3a=24
a=24/3
a=8
2... a=8
(8-d)(8)(8+d)=312
we take.. (8-d)(8+d)=312/8
( 8-d)(8+d)=39
8 square -d square =39
64-d square =39
64-39=d square
25=d square
d=root of 25
d= 5
a=8
d=5
the three consecutive numbers a-d=8-5=3
a=8
a+d=8+5=13
three numbers are 3.8.13
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