Question

Find three different irrational numbers between 4/9 and 8/11.

Answer 1

Step by step process
1) Find the diff. between these two numbers and divide it by 4.
2) First no. is 4/9 +x
second is 4/9+2x
third is 4/9 + 3x
3) You have got all your no.s

as i have solved, the difference/4 comes out to be 7/99.
Please mark as Brainliest.

Answer 2

irrational number between any two number a and b = $\sqrt{ab}$
irrational numbers between 4/9 and 8/11 = $\sqrt{ \frac{4}{9}. \frac{8}{11} }$
                                                              = $\frac{6}{3 \sqrt{11} }$
                                                               = $\frac{2}{\sqrt{11} }$
irrational numbers between 4/9 and $\frac{2}{\sqrt{11} }$ = $\sqrt{ \frac{4}{9}. \frac{2}{ \sqrt{11} } }$
                                                             = $\frac{2\sqrt{2}}{3 \sqrt{11} }$

irrational numbers between 8/11 and $\frac{2}{\sqrt{11} }$ = $\sqrt{ \frac{8}{11}. \frac{2}{ \sqrt{11} } }$
                                                             = $\frac{4}{ \sqrt{11 \sqrt{11}} }$

Therefore the three irrational numbers are $\frac{4}{ \sqrt{11 \sqrt{11}} }$ , $\frac{2\sqrt{2}}{3 \sqrt{11} }$ , $\frac{2}{\sqrt{11} }$