Question

Find three different solutions for the linear equation 3x+5y=16​

Answer 1

Step-by-step explanation:

The given equations are

3x−5y=−16 (1)

2x+5y=31 (2)

Note that the coefficients of y in both equations are numerically equal. So, we can eliminate y easily.

Adding (1) and (2), we obtain an equation

5x=15

That is, x=3 (3)

Now, we substitute x = 3 in (1) or (2) to solve for y.

Substituting x = 3 in (1) we obtain, 3(3)−5y=−16

→y=5

Now, (3, 5) a is solution to the given system because (1) and (2) are true when x = 3 and y = 5 as from (1) and (2) we get, 3(3)−5(5)=−16 and 2(3)+5(5)=31.

Answer 2

Answer:

Linear equations in two variables x and y will be

x+y=12x+3y=8x−y=65x−2y=3x+2y=3

Step-by-step explanation:

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