Question

find three different solutions of 2x+4y-6=0

Answer 1

Answer:

Three different solutions are

Three different solutions are (3,0), (1,1) and (-1,2)

Step-by-step explanation:

Given Linear equation in two variables : 2x+4y-6=0

/* Divide each term by 2, we get

=> x+2y-3=0

=> x = 3-2y ---(1)

i) if y = 0, then

x = 3-2×0 = 3

(3,0)

ii) If y = 1 then

x = 3-2×1 = 3-2 = 1

(1,1)

iii) If y = 2 then

x = 3-2×2= 3-4 = -1

(-1,2)

Therefore,

Three different solutions are

(3,0), (1,1) and (-1,2)

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