Find three different solutions of the each of the following equations. 1.(3x+4y=7) 2.(y=6x) 3.(2x-y=7) 4.(13x-12y=25) 5.(10x+11y=21) 6.(x+y=0)
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Answer:
terms
in its
Auct of
6.XY
What about the last two terms? Observe the
Il you change their order to - 9x+6, the fa
(3x - 2) will come out
9x+6= - 3 (3x) + 3 (2)
- 3 (312)
Step 3. Putting (a) and (b) together,
6xy - 4y + 6 - 9x6xy - 4y - 9x + 6
Be Practice to be Perfect 1
1 Factorise:
(1) %* (3x - y) + 7y (3x - y)
(11) 27a(2x - 8) + 36 (2x - 8)
(v) 15(x + 2y) + 3(x+2y)
or is of
ce you
factor
given
Book)
Factorisation of Algebraic Expressions
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